Question

The value of $k$ for which the roots of the equation $x^2+2(k+1)x+k^2=0$ are equal to

• A. $-1$
• B. $-\frac{1}{2}$
• C. $1$
• D. $\frac{1}{2}$

Answer 1

Answer: (B)

Since roots of the equation
$x^2+2(k+1)x+k^2=0$
are equal.
$\therefore$ $B^2=4AC$
$\Rightarrow$ $4{(k+1)}^2=4k^2$
$\Rightarrow$ $4k^2+4+8k=4k^2$
$\Rightarrow$ $k=-\frac{1}{2}$