The value of ∫ cos ( log x) dx is :

Question

The value of ∫ cos ( log x) dx is : (A) (1/2)[ sin ( log x)+ cos ( log x)]+ C (B) (x/2)[ sin ( log x)+ cos ( log x)]+ C (C) (x/2)[ sin ( log x)- cos ( log x)]+ C (D) (1/2)[ sin ( log x)- cos ( log x)]+C

Tardigrade Admin · Accepted Answer

Correct answer is (b) (x/2)[ sin ( log x)+ cos ( log x)]+ C

Q. The value of $\int cos (lo g x) d x$ is :

$\frac{1}{2} [sin (lo g x) + cos (lo g x)] + C$

$\frac{x}{2} [sin (lo g x) + cos (lo g x)] + C$

$\frac{x}{2} [sin (lo g x) - cos (lo g x)] + C$

$\frac{1}{2} [sin (lo g x) - cos (lo g x)] + C$

Correct answer is (b) $\frac{x}{2} [sin (lo g x) + cos (lo g x)] + C$

Q. The value of ∫cos(logx)dx is :

21​[sin(logx)+cos(logx)]+C

2x​[sin(logx)+cos(logx)]+C

2x​[sin(logx)−cos(logx)]+C

21​[sin(logx)−cos(logx)]+C