Question

The value of definite integral $\pi \underset{0}{\overset{\pi }{\int }}\frac{x^2\sin 2x\sin \left(\frac{\pi }{2}\cos x\right)}{2x-\pi }dx$ equals

• A. 2
• B. 4
• C. 8
• D. 16

Answer 1

Answer: (C)

Correct answer is (c) 8