Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The value of 4 sin A cos3 A - 4 cos A sin3 A is equal to
Q. The value of
4
s
in
A
co
s
3
A
−
4
cos
A
s
i
n
3
A
is equal to
2037
255
Trigonometric Functions
Report Error
A
cos
2
A
13%
B
s
in
3
A
19%
C
s
in
2
A
18%
D
s
in
4
A
51%
Solution:
4
s
in
A
co
s
3
A
−
4
cos
A
s
i
n
3
A
=
4
s
in
A
cos
A
(
co
s
2
A
−
s
i
n
2
A
)
=
2
s
in
2
A
cos
2
A
=
s
in
4
A
.