The value of (4 ⋅ n C1+4 ⋅ n C2+42 ⋅ n C3+ ldots ldots+4n-1) is

Question

The value of (4 ⋅ n C1+4 ⋅ n C2+42 ⋅ n C3+ ldots ldots+4n-1) is (A) 0 (B) 5n+1 (C) 5 n  (D) 5 n -1

Tardigrade Admin · Accepted Answer

text Given E =4 ⋅ n C 1+42 ⋅ n C 2+43 ⋅ n C 3+ ldots ldots .+4 n ⋅ n C n =(1+4)n-1 ⇒ 5n-1 ⇒ D

Q. The value of $(4 \cdot^{n} C_{1} + 4 \cdot^{n} C_{2} + 4^{2} \cdot^{n} C_{3} + \dots\dots + 4^{n - 1})$ is