Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
Sum of the digits in the value of (1+ tan 5°)(1+ tan 10°)(1+ tan 15°) ldots (1+ tan 45°)= is.
Q. Sum of the digits in the value of
(
1
+
tan
5
∘
)
(
1
+
tan
1
0
∘
)
(
1
+
tan
1
5
∘
)
…
(
1
+
tan
4
5
∘
)
=
is______.
416
170
Trigonometric Functions
Report Error
Answer:
5
Solution:
(
1
+
tan
θ
)
(
1
+
tan
(
4
5
∘
−
θ
)
)
=
(
1
+
tan
θ
)
(
1
+
1
+
t
a
n
θ
1
−
t
a
n
θ
)
=
(
1
+
tan
θ
)
(
1
+
t
a
n
θ
2
)
=
2
Hence
L
H
S
=
2
(
1
+
tan
5
∘
)
(
1
+
tan
4
0
∘
)
(
1
+
tan
1
0
∘
)
(
1
+
tan
3
5
∘
)
(
1
+
tan
1
5
∘
)
(
1
+
tan
3
0
∘
)
(
1
+
tan
2
0
∘
)
(
1
+
tan
2
5
∘
)
=
2
⋅
2
4
=
2
5