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Tardigrade
Question
Mathematics
The value of (1-ω+ω2)(1-ω2+ω4)(1-ω4+ω8) ldots ldots ldots. to 2 n factors is
Q. The value of
(
1
−
ω
+
ω
2
)
(
1
−
ω
2
+
ω
4
)
(
1
−
ω
4
+
ω
8
)
………
. to
2
n
factors is
43
166
Complex Numbers and Quadratic Equations
Report Error
A
2
n
B
4
n
C
4
n
D
2
n
Solution:
(
1
−
ω
+
ω
2
)
(
1
+
ω
4
−
ω
2
)
=
(
−
2
ω
)
(
−
2
ω
2
)
=
4
similarly total we have and terms and each equal to 4
∴
Ans.
=
4
n