The unit of Stefan's constant is

Question

The unit of Stefan's constant is (A) Wm-2k-1 (B) Wmk-4 (C) Wm-2k-4 (D) Nm-2k4

Tardigrade Admin · Accepted Answer

According to Stefan's law, the energy radiated per second or power radiated is given by P=σ A T4 σ=(P/A T4) Therefore, unit of σ=( W / m 2 K 4)= Wm -2 K -4

Q. The unit of Stefan's constant is

$W m^{- 2} k^{- 1}$

$Wm k^{- 4}$

$W m^{- 2} k^{- 4}$

$N m^{- 2} k^{4}$

According to Stefan's law, the energy radiated per second or power radiated is given by
$P = σ A T^{4}$
$σ = \frac{P}{A T ^{4}}$
Therefore, unit of $σ = \frac{W}{m ^{2} K ^{4}} = W m^{- 2} K^{- 4}$

Q. The unit of Stefan's constant is

Wm−2k−1

Wmk−4

Wm−2k−4

Nm−2k4

According to Stefan's law, the energy radiated per second or power radiated is given by P=σAT4 σ=AT4P​ Therefore, unit of σ=m2K4W​=Wm−2K−4

$W m^{- 2} k^{- 1}$

$Wm k^{- 4}$

$W m^{- 2} k^{- 4}$

$N m^{- 2} k^{4}$

According to Stefan's law, the energy radiated per second or power radiated is given by
$P = σ A T^{4}$
$σ = \frac{P}{A T ^{4}}$
Therefore, unit of $σ = \frac{W}{m ^{2} K ^{4}} = W m^{- 2} K^{- 4}$