The unit JPa-1 is equivalent to

Question

The unit JPa-1 is equivalent to (A) m3 (B) cm3 (C) dm3 (D) None of these

Tardigrade Admin · Accepted Answer

JPa1; Unit of work is Joule and unit of pressure is Pascal. Dimension of Joule, i.e., work = F × = MLT-2× L= [ML2T-2] (1/Pa)=(1/Pressure)=(1/F/A)=(1× A/F)=[M-1LT-2] So, JPa-1=[L2× L] =[L3]

Q. The unit $J P a^{- 1}$ is equivalent to

$m^{3}$

$c m^{3}$

$d m^{3}$

None of these

Q. The unit JPa−1 is equivalent to

m3

cm3

dm3

None of these

JPa1; Unit of work is Joule and unit of pressure is Pascal. Dimension of Joule, i.e., work =F×=MLT−2×L=[ML2T−2] Pa1​=Pressure1​=F/A1​=F1×A​=[M−1LT−2] So, JPa−1=[L2×L]=[L3]

Q. The unit $J P a^{- 1}$ is equivalent to

$m^{3}$

$c m^{3}$

$d m^{3}$