The uncertainty in velocity of an electron present in the nucleus of diameter 10-15 m hypothetically should be approximately

Question

The uncertainty in velocity of an electron present in the nucleus of diameter 10-15 m hypothetically should be approximately (A) 10-11 m / s (B) 108 m / s (C) 1011 m / s (D) 10 mathringA / s

Tardigrade Admin · Accepted Answer

Δ x=10-15 m m=9.1 × 10-31 kg Δ x × m Δ v =( h /4 π) ⇒ Δ v =(6.6 × 10-34 kg m 2 s -1/10-15 × 9.1 × 10-31 × 4 × 3.14) =(6.6/114.296) × 1012 m / s App. =0.5 × 1011 m / s

Q. The uncertainty in velocity of an electron present in the nucleus of diameter $1 0^{- 15} m$ hypothetically should be approximately

$1 0^{- 11} m / s$

$1 0^{8} m / s$

$1 0^{11} m / s$

$10 \overset{˚}{A} / s$

Q. The uncertainty in velocity of an electron present in the nucleus of diameter 10−15m hypothetically should be approximately

10−11m/s

108m/s

1011m/s

10A˚/s

Δx=10−15m m=9.1×10−31kg Δx×mΔv=4πh​ ⇒Δv=10−15×9.1×10−31×4×3.146.6×10−34kgm2s−1​ =114.2966.6​×1012m/s App. =0.5×1011m/s

Q. The uncertainty in velocity of an electron present in the nucleus of diameter $1 0^{- 15} m$ hypothetically should be approximately

$1 0^{- 11} m / s$

$1 0^{8} m / s$

$1 0^{11} m / s$

$10 \overset{˚}{A} / s$