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Question
Chemistry
The total number of possible isomers of the complex compound [C uI I(N H3)4][P tI I C l4] is:
Q. The total number of possible isomers of the complex compound
[
C
u
II
(
N
H
3
)
4
]
[
P
t
II
C
l
4
]
is:
1830
218
Delhi UMET/DPMT
Delhi UMET/DPMT 2004
Report Error
A
3
B
6
C
5
D
4
Solution:
The following isomers are possible by this formula:
(i)
[
C
u
(
N
H
3
)
4
]
[
PtC
l
4
]
(ii)
[
C
u
(
N
H
3
)
3
Cl
]
[
PtC
l
3
(
N
H
3
)
]
(iii)
[
C
u
(
N
H
3
)
2
C
l
2
]
[
PtC
l
2
(
N
H
3
)
2
]
(iv)
[
C
u
(
N
H
3
)
C
l
3
]
[
PtCl
(
N
H
3
)
3
]
(v)
[
C
u
C
l
4
]
[
Pt
(
N
H
3
)
4
]