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Tardigrade
Question
Chemistry
The total number of possible isomers for the complex compound [Cu(NH3)4] [PtCl4]
Q. The total number of possible isomers for the complex compound
[
C
u
(
N
H
3
)
4
]
[
PtC
l
4
]
2405
281
CMC Medical
CMC Medical 2014
Report Error
A
6
B
5
C
4
D
3
Solution:
1.
[
C
u
(
N
H
3
)
4
]
⋅
[
PtC
l
4
]
2.
[
C
u
(
N
H
3
)
3
Cl
]
⋅
[
PtC
l
3
(
N
H
3
)]
3.
[
C
u
(
N
H
3
)
2
C
l
2
]
⋅
[
PtC
l
2
(
N
H
3
)
2
]
c
i
s
4.
[
C
u
(
N
H
3
)
2
C
l
2
]
⋅
[
PtC
l
2
(
N
H
3
)
2
]
t
r
an
s
5.
[
C
u
(
N
H
3
)
C
l
3
]
⋅
[
Pt
(
Cl
)
(
N
H
3
)
3
]
6.
[
Pt
(
N
H
3
)
4
]
⋅
[
C
u
C
l
4
]