The tension T in the string shown in figure is

Question

The tension T in the string shown in figure is (A) Zero (B) 50 N (C) 35 √3 N (D) (√3-1) 50 N

Tardigrade Admin · Accepted Answer

m g sin θ=10(10) sin 30°=50 N Frictional force =μ mg cos θ =(0.7)(10)(10) (√3/2)=35 √3 N Frictional force is sufficient to oppose gravitational force. Tension will be zero.

Q. The tension $T$ in the string shown in figure is

Zero

50 N

$353 N$

$(3 - 1) 50 N$

$m g sin θ = 10 (10) sin 3 0^{\circ} = 50 N$
Frictional force $= μ m g cos θ$
$= (0.7) (10) (10) \frac{3}{2} = 353 N$
Frictional force is sufficient to oppose gravitational force.
Tension will be zero.

Q. The tension T in the string shown in figure is

Zero

50 N

353​N

(3​−1)50N

mgsinθ=10(10)sin30∘=50N Frictional force =μmgcosθ =(0.7)(10)(10)23​​=353​N Frictional force is sufficient to oppose gravitational force. Tension will be zero.

Q. The tension $T$ in the string shown in figure is

$353 N$

$(3 - 1) 50 N$

$m g sin θ = 10 (10) sin 3 0^{\circ} = 50 N$
Frictional force $= μ m g cos θ$
$= (0.7) (10) (10) \frac{3}{2} = 353 N$
Frictional force is sufficient to oppose gravitational force.
Tension will be zero.