The temperature at which a perfect black body radiates at the rate of 5.67 W cm-2 is (Stefan's constant is 5.67 ×10-8 Js-1m-2 K-4 .)

Question

The temperature at which a perfect black body radiates at the rate of 5.67 W cm-2 is (Stefan's constant is 5.67 ×10-8 Js-1m-2 K-4 .) (A) 1000 K (B) 2000 K (C) 109.2 K (D) 3388 K.

Tardigrade Admin · Accepted Answer

E=5.67 W cm-2=5.67×10+4Wm-2; σ=5.67×10-8Js-1m-2k-4 Using E=σ T4;T4=(E/σ) or T=((E/σ))1/4=((5.67× 10-8/5.67×10+4))1/4=(1012)1/4=1000 K

Q. The temperature at which a perfect black body radiates at the rate of $5.67 W$ $c m^{- 2}$ is (Stefan's constant is $5.67 \times 1 0^{- 8} J s^{- 1} m^{- 2} K^{- 4}$ .)

1000 K

2000 K

109.2 K

3388 K.

$E = 5.67 W c m^{- 2} = 5.67 \times 1 0^{+ 4} W m^{- 2};$
$σ = 5.67 \times 1 0^{- 8} J s^{- 1} m^{- 2} k^{- 4}$
$U s in g E = σ T^{4}; T^{4} = \frac{E}{σ} or$
$T = (\frac{E}{σ})^{1/4} = (\frac{5.67 \times 1 0 ^{- 8}}{5.67 \times 1 0 ^{+ 4}})^{1/4} = (1 0^{12})^{1/4} = 1000 K$

Q. The temperature at which a perfect black body radiates at the rate of 5.67W cm−2 is (Stefan's constant is 5.67×10−8Js−1m−2K−4 .)