The system of two weights of masses m1 and m2 are connected with weight less spring as shown. The system is resting on the support S . If the support S is quickly removed then acceleration of each weight just after the removal of S are :- [Given ⇒ m1=m &m2=2m ]

Question

The system of two weights of masses m1 and m2 are connected with weight less spring as shown. The system is resting on the support S . If the support S is quickly removed then acceleration of each weight just after the removal of S are :- [Given ⇒ m1=m &m2=2m ] <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-of4oa4hlt6z27xtp.jpg" /> (A) a1=gms- 2,a2=2gms- 2 (B) a1=g/2ms- 2,a2=(1/3)gms- 2 (C) a1=0,a2=(3/2)gms2 (D) a1=(2/3)gms- 2,a2=0

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-of4oa4hlt6z2os4o.jpg" /> Fsp=m1g Now if N=0 then it will have no effect on m1 instantly so a1=0 but m2 will exp. net downward force so (m2 g + Fsp)=m2a2 (m1 + m2)g=m2a2 ⇒ a2=(3/2)g

$a_{1} = g m s^{- 2}, a_{2} = 2 g m s^{- 2}$

$a_{1} = g /2 m s^{- 2}, a_{2} = \frac{1}{3} g m s^{- 2}$

$a_{1} = 0, a_{2} = \frac{3}{2} g m s^{2}$

$a_{1} = \frac{2}{3} g m s^{- 2}, a_{2} = 0$

$F_{s p} = m_{1} g$
Now if $N = 0$ then it will have no effect on $m_{1}$
instantly so $a_{1} = 0$ but $m_{2}$ will exp. net
downward force so $(m_{2 g} + F_{s p}) = m_{2} a_{2}$
$(m_{1} + m_{2}) g = m_{2} a_{2}$
$\Rightarrow a_{2} = \frac{3}{2} g$

Q. The system of two weights of masses m1​ and m2​ are connected with weight less spring as shown. The system is resting on the support S . If the support S is quickly removed then acceleration of each weight just after the removal of S are :- [Given ⇒m1​=m&m2​=2m ]

a1​=gms−2,a2​=2gms−2

a1​=g/2ms−2,a2​=31​gms−2

a1​=0,a2​=23​gms2

a1​=32​gms−2,a2​=0

Fsp​=m1​g Now if N=0 then it will have no effect on m1​ instantly so a1​=0 but m2​ will exp. net downward force so (m2g​+Fsp​)=m2​a2​ (m1​+m2​)g=m2​a2​ ⇒a2​=23​g

$a_{1} = g m s^{- 2}, a_{2} = 2 g m s^{- 2}$

$a_{1} = g /2 m s^{- 2}, a_{2} = \frac{1}{3} g m s^{- 2}$

$a_{1} = 0, a_{2} = \frac{3}{2} g m s^{2}$

$a_{1} = \frac{2}{3} g m s^{- 2}, a_{2} = 0$

$F_{s p} = m_{1} g$
Now if $N = 0$ then it will have no effect on $m_{1}$
instantly so $a_{1} = 0$ but $m_{2}$ will exp. net
downward force so $(m_{2 g} + F_{s p}) = m_{2} a_{2}$
$(m_{1} + m_{2}) g = m_{2} a_{2}$
$\Rightarrow a_{2} = \frac{3}{2} g$