Question

The system of equations $2x+3y=7,14x+21y=49$ has

• A. infinitely many solutions
• B. a unique solution
• C. no solution
• D. finitely many solutions

Answer 1

Answer: (A)

Let A = $\left[\begin{array}{cc}2& 3\\ 14& 21\end{array}\right]$ , det A = 0
Clearly, the given system has infinitely many solutions.
$\because$ $7(2x+3y)=7\times 7$
given $14x+21y=49$