The synthesis of 3 - octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are

Question

The synthesis of 3 - octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are (A) BrCH 2 CH 2 CH 2 CH 2 CH 3 and CH 3 CH 2 C ≡ CH (B) BrCH 2 CH 2 CH 3 and CH 3 CH 2 CH 2 C ≡ CH (C) Br CH 2 CH 2 CH 2 CH 2 CH 3 and CH 3 C ≡ CH (D) BrCH 2 CH 2 CH 2 CH 3 and CH 3 CH 2 C ≡ CH

Tardigrade Admin · Accepted Answer

CH 3- CH 2- C ≡ CH ->[ NaNH ,]CH 3- CH 2- C ≡ C - Na + CH 3- CH 2- CH 2- CH 2 Br + Na - C ≡ C - CH 2- CH 3 longrightarrow underset text3 -octyneCH 3- CH 2- CH 2- CH 2- C ≡ C - CH 2- CH 3

Q. The synthesis of $3$ - octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are

$B r C H_{2} C H_{2} C H_{2} C H_{2} C H_{3}$ and $C H_{3} C H_{2} C \equiv C H$

$B r C H_{2} C H_{2} C H_{3}$ and $C H_{3} C H_{2} C H_{2} C \equiv C H$

$B r C H_{2} C H_{2} C H_{2} C H_{2} C H_{3}$ and $C H_{3} C \equiv C H$

$B r C H_{2} C H_{2} C H_{2} C H_{3}$ and $C H_{3} C H_{2} C \equiv C H$

$C H_{3} - C H_{2} - C \equiv C H NaNH , C H_{3} - C H_{2} - C \equiv C^{-} N a^{+}$
$C H_{3} - C H_{2} - C H_{2} - C H_{2} B r + N a - C \equiv C - C H_{2} - C H_{3} ⟶ 3 -octyne C H_{3} - C H_{2} - C H_{2} - C H_{2} - C \equiv C - C H_{2} - C H_{3}$

Q. The synthesis of 3 - octyne is achieved by adding a bromoalkane into a mixture of sodium amide and an alkyne. The bromoalkane and alkyne respectively are

BrCH2​CH2​CH2​CH2​CH3​ and CH3​CH2​C≡CH

BrCH2​CH2​CH3​ and CH3​CH2​CH2​C≡CH

BrCH2​CH2​CH2​CH2​CH3​ and CH3​C≡CH

BrCH2​CH2​CH2​CH3​ and CH3​CH2​C≡CH