The sum of two positive integers is at most 5. The difference between two times of second number and first number is at most 4. If the first number is x and second number y, then for maximizing the product of these two numbers, the mathematical formulation is

Question

The sum of two positive integers is at most 5. The difference between two times of second number and first number is at most 4. If the first number is x and second number y, then for maximizing the product of these two numbers, the mathematical formulation is (A) x + y ≥ 5 , 2y - x ≥ 4 , x ≥ 0 , y ≥ 0  (B) x + y ≥ 5 , -2x + y ≥ 4 , x ≥ 0 , y ≥ 0  (C) x + y ≤ 5 , 2y - x ≤ 4 , x ≥ 0 , y ≥ 0  (D) None of these

Tardigrade Admin · Accepted Answer

Obviously x + y ≤ 5 , 2y - x ≤ 4, x ≥ 0 , y ≥ 0 .

Q. The sum of two positive integers is at most 5. The difference between two times of second number and first number is at most 4. If the first number is x and second number y, then for maximizing the product of these two numbers, the mathematical formulation is

$x + y \geq 5, 2 y - x \geq 4, x \geq 0, y \geq 0$

$x + y \geq 5, - 2 x + y \geq 4, x \geq 0, y \geq 0$

$x + y \leq 5, 2 y - x \leq 4, x \geq 0, y \geq 0$

None of these

Obviously $x + y \leq 5, 2 y - x \leq 4, x \geq 0, y \geq 0.$

Q. The sum of two positive integers is at most 5. The difference between two times of second number and first number is at most 4. If the first number is x and second number y, then for maximizing the product of these two numbers, the mathematical formulation is

x+y≥5,2y−x≥4,x≥0,y≥0

x+y≥5,−2x+y≥4,x≥0,y≥0

x+y≤5,2y−x≤4,x≥0,y≥0

None of these

Obviously x+y≤5,2y−x≤4,x≥0,y≥0.

$x + y \geq 5, 2 y - x \geq 4, x \geq 0, y \geq 0$

$x + y \geq 5, - 2 x + y \geq 4, x \geq 0, y \geq 0$

$x + y \leq 5, 2 y - x \leq 4, x \geq 0, y \geq 0$

Obviously $x + y \leq 5, 2 y - x \leq 4, x \geq 0, y \geq 0.$