Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The sum of the series ( 101 C1/ 101 C0)+(2 ⋅ 101 C2/ 101 C1)+(3 ⋅ 101 C3/ 101 C2)+ ldots+(101 ⋅ 101 C101/ 101 C100) equals
Q. The sum of the series
101
C
0
101
C
1
+
101
C
1
2
⋅
101
C
2
+
101
C
2
3
⋅
101
C
3
+
…
+
101
C
100
101
⋅
101
C
101
equals
1339
162
Binomial Theorem
Report Error
Answer:
5151
Solution:
Consider the general term
T
r
=
101
C
r
−
1
r
⋅
101
C
r
which simplifies to
(
102
−
r
)
hence sum
=
r
=
1
∑
101
102
−
r
=
101
+
100
+
99
+
…
+
2
+
1
=
5151