The sum of the number of lone pairs of electrons on each central atom in the following species is [ TeBr 6]2-,[ BrF 2]+and [ XeF 3]- (Atomic number: F =9, Br =35, Te =52, Xe = 54)

Question

The sum of the number of lone pairs of electrons on each central atom in the following species is [ TeBr 6]2-,[ BrF 2]+and [ XeF 3]- (Atomic number: F =9, Br =35, Te =52, Xe = 54) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Species Lone pair on central atom [.TeBr6].2 - 1 BrF2+ 2 XeF3- 3 Total number of lone pair = 6.

Species	Lone pair on central atom
$[T e B r_{6}]^{2 -}$	1
$B r F_{2}^{+}$	2
$X e F_{3}^{-}$	3

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is
$[T e B r_{6}]^{2 -}, [B r F_{2}]^{+}$ and $[X e F_{3}]^{-}$
(Atomic number: $F = 9, B r = 35, T e = 52, X e = 54$ )

Species Lone pair on central atom

$[T e B r_{6}]^{2 -}$ 1

$B r F_{2}^{+}$ 2

$X e F_{3}^{-}$ 3

Total number of lone pair $= 6$ .

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr6​]2−,[BrF2​]+and [XeF3​]− (Atomic number: F=9,Br=35,Te=52,Xe=54)

Species Lone pair on central atom [TeBr6​]2− 1 BrF2+​ 2 XeF3−​ 3 Total number of lone pair =6.

Q. The sum of the number of lone pairs of electrons on each central atom in the following species is
$[T e B r_{6}]^{2 -}, [B r F_{2}]^{+}$ and $[X e F_{3}]^{-}$
(Atomic number: $F = 9, B r = 35, T e = 52, X e = 54$ )

Species Lone pair on central atom

$[T e B r_{6}]^{2 -}$ 1

$B r F_{2}^{+}$ 2

$X e F_{3}^{-}$ 3

Total number of lone pair $= 6$ .