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Question
Mathematics
The sum of last two digits of the number 7101 is
Q. The sum of last two digits of the number
7
101
is ___
1612
194
Binomial Theorem
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Answer:
7
Solution:
7
101
=
7
(
49
)
50
=
7
(
1
−
50
)
50
=
7
[
50
C
0
−
50
C
1
50
+
50
C
2
5
0
2
−
…
]
=
7
[
1
+
100
λ
]
where
λ
∈
N
=
7
+
700
λ
Therefore, last two digits of number
7
101
are
07
.