The total number of numbers that can be formed with the digits 2,3,4,5 taken all at a time =4P4=4!=24.
Consider the digit in the unit's place in all these numbers.
Each of the digits 2,3,4,5 occurs in 3!=6 times in the unit's place ∴ total for the digits in the unit's place =(2+3+4+5)6=84
Since each of the digits 2,3,4,5 occurs 6 times in any one of the remaining places ∴ the required total =84(1+10+102+103)=84(1111)=93324