Question

The sum of all the numbers formed by using the digits 7, 8, 9 is

• A. 5328
• B. 5325
• C. 5345
• D. 5348

Answer 1

Answer: (A)

Reqd. sum $=\left(7+8+9\right)\times 2!\times \left(111\right)$
$=48\times 111=5328$