The structure of the compound that gives a tribromo derivative on treatment with bromine water is

Question

The structure of the compound that gives a tribromo derivative on treatment with bromine water is (A) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1f287e2667e6cb17becd6f6ee4f4b881-.png" /> (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since the compound on treatment with Br 2 -water gives a tribromo derivative, therefore it must be m -cresol, because it has two ortho and one para position free with respect to OH group and hence can give tribromoderivative. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/555b847c92186ae63f5f0e5a00e25e0e-.png" />

Q. The structure of the compound that gives a tribromo derivative on treatment with bromine water is

Since the compound on treatment with $B r_{2}$ -water gives a tribromo derivative, therefore it must be $m$ -cresol, because it has two ortho and one para position free with respect to $O H$ group and hence can give tribromoderivative.

Q. The structure of the compound that gives a tribromo derivative on treatment with bromine water is

Since the compound on treatment with Br2​ -water gives a tribromo derivative, therefore it must be m -cresol, because it has two ortho and one para position free with respect to OH group and hence can give tribromoderivative.

Since the compound on treatment with $B r_{2}$ -water gives a tribromo derivative, therefore it must be $m$ -cresol, because it has two ortho and one para position free with respect to $O H$ group and hence can give tribromoderivative.