The stress required to double the length of wire of Young's modulus Y is

Question

The stress required to double the length of wire of Young's modulus Y is (A)  (Y/2)  (B)  2Y  (C)  Y  (D)  4 y

Tardigrade Admin · Accepted Answer

Let L be the length of a wire. If the length of a wire is doubled, the longitudinal strain will be (Δ L / L )=(2 L - L / L )=( L / L )=1 Young's modulus Y =( text Stress / text Strain ) ∴ Y = Stress (∵ Strain =1).

Q. The stress required to double the length of wire of Young's modulus $Y$ is

$\frac{Y}{2}$

$2 Y$

$Y$

$4 y$

Let $L$ be the length of a wire.
If the length of a wire is doubled, the longitudinal strain will be
$\frac{Δ L}{L} = \frac{2 L - L}{L} = \frac{L}{L} = 1$
Young's modulus $Y = \frac{Stress}{Strain}$
$∴ Y =$ Stress $(∵$ Strain $= 1)$ .

Q. The stress required to double the length of wire of Young's modulus Y is

2Y​

2Y

Y

4y

Let L be the length of a wire. If the length of a wire is doubled, the longitudinal strain will be LΔL​=L2L−L​=LL​=1 Young's modulus Y= Strain Stress ​ ∴Y= Stress (∵ Strain =1).

Q. The stress required to double the length of wire of Young's modulus $Y$ is

$\frac{Y}{2}$

$2 Y$

$Y$

$4 y$

Let $L$ be the length of a wire.
If the length of a wire is doubled, the longitudinal strain will be
$\frac{Δ L}{L} = \frac{2 L - L}{L} = \frac{L}{L} = 1$
Young's modulus $Y = \frac{Stress}{Strain}$
$∴ Y =$ Stress $(∵$ Strain $= 1)$ .