The star which appears blue must be

Question

The star which appears blue must be (A) very cold (B) colder than the Sun (C) a black hole (D) hotter than the Sun

Tardigrade Admin · Accepted Answer

From Wein's displacement law, λ m a x=(b/T) Also, λ propto (1/ν) Therefore, ν propto T, ν is the frequency of the radiation and T is the absolute temperature of source. Thus, we can say that the blue star is hotter than the white star i.e. the Sun.

Q. The star which appears blue must be

very cold

colder than the Sun

a black hole

hotter than the Sun

From Wein's displacement law,
$λ_{ma x} = \frac{b}{T}$
Also, $λ \propto \frac{1}{ν}$
Therefore, $ν \propto T,$ $ν$ is the frequency of the radiation and $T$ is the absolute temperature of source.
Thus, we can say that the blue star is hotter than the white star i.e. the Sun.

Q. The star which appears blue must be

very cold

colder than the Sun

a black hole

hotter than the Sun

From Wein's displacement law, λmax​=Tb​ Also, λ∝ν1​ Therefore, ν∝T, ν is the frequency of the radiation and T is the absolute temperature of source. Thus, we can say that the blue star is hotter than the white star i.e. the Sun.

From Wein's displacement law,
$λ_{ma x} = \frac{b}{T}$
Also, $λ \propto \frac{1}{ν}$
Therefore, $ν \propto T,$ $ν$ is the frequency of the radiation and $T$ is the absolute temperature of source.
Thus, we can say that the blue star is hotter than the white star i.e. the Sun.