The speed of sound in a gas is v. The r.m.s. velocity of the gas molecules is C. The ratio of v to C is

Question

The speed of sound in a gas is v. The r.m.s. velocity of the gas molecules is C. The ratio of v to C is (A) 3/ &gamma; (B)  &gamma; / 3  (C) √(3 / &gamma;) (D) √(&gamma; / 3 )

Tardigrade Admin · Accepted Answer

The speed of sound in gas is given by: v =√(&gamma; RT / M ) The RMS velocity is given by: c=√(3 R T/M) The ratio of v to c is: ( v / c )=√(&gamma;/3)

Q. The speed of sound in a gas is v. The r.m.s. velocity of the gas molecules is C. The ratio of v to C is

$3/ γ$

$γ /3$

$(3/ γ)$

$(γ /3)$

The speed of sound in gas is given by:
$< b r / > v = \frac{γ RT}{M} < b r / >$
The RMS velocity is given by:
$< b r / > c = \frac{3 RT}{M} < b r / >$
The ratio of $v$ to $c$ is:
$< b r / > \frac{v}{c} = \frac{γ}{3} < b r / >$

Q. The speed of sound in a gas is v. The r.m.s. velocity of the gas molecules is C. The ratio of v to C is

3/γ

γ/3

(3/γ)​

(γ/3)​

The speed of sound in gas is given by: <br/>v=MγRT​​<br/> The RMS velocity is given by: <br/>c=M3RT​​<br/> The ratio of v to c is: <br/>cv​=3γ​​<br/>

$3/ γ$

$γ /3$

$(3/ γ)$

$(γ /3)$

The speed of sound in gas is given by:
$< b r / > v = \frac{γ RT}{M} < b r / >$
The RMS velocity is given by:
$< b r / > c = \frac{3 RT}{M} < b r / >$
The ratio of $v$ to $c$ is:
$< b r / > \frac{v}{c} = \frac{γ}{3} < b r / >$