The speed of electromagnetic wave in a medium of dielectric constant 2.25 and relative permeability 4 is

Question

The speed of electromagnetic wave in a medium of dielectric constant 2.25 and relative permeability 4 is (A) 1× 108 m/s (B) 2.5 × 108 m/s (C) 2 × 108 m/s (D) 3 × 108 m/s

Tardigrade Admin · Accepted Answer

v=(3× 108/√2.25×4)=(3 × 108/√9)=(3 ×108/3)=1× 108 m s-1

Q. The speed of electromagnetic wave in a medium of dielectric constant 2.25 and relative permeability 4 is

$1 \times 1 0^{8} m / s$

$2.5 \times 1 0^{8} m / s$

$2 \times 1 0^{8} m / s$

$3 \times 1 0^{8} m / s$

$v = \frac{3 \times 1 0 ^{8}}{2.25 \times 4} = \frac{3 \times 1 0 ^{8}}{9} = \frac{3 \times 1 0 ^{8}}{3} = 1 \times 1 0^{8} m s^{- 1}$

Q. The speed of electromagnetic wave in a medium of dielectric constant 2.25 and relative permeability 4 is

1×108m/s

2.5×108m/s

2×108m/s

3×108m/s

v=2.25×4​3×108​=9​3×108​=33×108​=1×108ms−1

$1 \times 1 0^{8} m / s$

$2.5 \times 1 0^{8} m / s$

$2 \times 1 0^{8} m / s$

$3 \times 1 0^{8} m / s$

$v = \frac{3 \times 1 0 ^{8}}{2.25 \times 4} = \frac{3 \times 1 0 ^{8}}{9} = \frac{3 \times 1 0 ^{8}}{3} = 1 \times 1 0^{8} m s^{- 1}$