The spectrum of a black body at two temperatures 227° C and 527° C as shown in graphical representation. Let A 1 A2 be the areas under the two curves respectively. The ratio of A 2 / A1 is:

Question

The spectrum of a black body at two temperatures 227° C and 527° C as shown in graphical representation. Let A 1 A2 be the areas under the two curves respectively. The ratio of A 2 / A1 is: (A) (5 / 8)2 (B) (2)4 (C) 1 (D) (5 / 8)4

Tardigrade Admin · Accepted Answer

(A2/A1)=((T1/T2))4=((500/800))4=(625/4096)

Q. The spectrum of a black body at two temperatures $22 7^{\circ} C$ and $52 7^{\circ} C$ as shown in graphical representation. Let $A_{1}$ $& A_{2}$ be the areas under the two curves respectively. The ratio of $A_{2} / A_{1}$ is:

$(5/8)^{2}$

$(2)^{4}$

1

$(5/8)^{4}$

$\frac{A _{2}}{A _{1}} = (\frac{T _{1}}{T _{2}})^{4} = (\frac{500}{800})^{4} = \frac{625}{4096}$

Q. The spectrum of a black body at two temperatures 227∘C and 527∘C as shown in graphical representation. Let A1​ &A2​ be the areas under the two curves respectively. The ratio of A2​/A1​ is:

(5/8)2

(2)4

1

(5/8)4

A1​A2​​=(T2​T1​​)4=(800500​)4=4096625​

Q. The spectrum of a black body at two temperatures $22 7^{\circ} C$ and $52 7^{\circ} C$ as shown in graphical representation. Let $A_{1}$ $& A_{2}$ be the areas under the two curves respectively. The ratio of $A_{2} / A_{1}$ is:

$(5/8)^{2}$

$(2)^{4}$

$(5/8)^{4}$

$\frac{A _{2}}{A _{1}} = (\frac{T _{1}}{T _{2}})^{4} = (\frac{500}{800})^{4} = \frac{625}{4096}$