The specific resistance of wire of length 1 m, area .of cross-section 0.5 m2 is 25 μ Ω m . The resistance of the wire will be:

Question

The specific resistance of wire of length 1 m, area .of cross-section 0.5 m2 is 25 μ Ω m . The resistance of the wire will be: (A)  5× 10-5 Ω  (B)  3× 10-6 Ω  (C)  46× 106 Ω  (D)  2× 106 Ω

Tardigrade Admin · Accepted Answer

Resistance R of a given conductor, at a constant temperature, is directly proportional to its length and inversely proportional to its area of cross-section A. i.e., R propto (l/A) or R=ρ (l/A) where ρ is called the specific resistance of the material. Given, ρ=25 × 10-6 Ω m, l=1 m, A=0.5 m 2 R=(25 × 10-6 × 1/0.5) =50 × 10-6 =5 × 10-5 Ω

Q. The specific resistance of wire of length 1 m, area .of cross-section $0.5 m^{2}$ is $25 μ Ω m$ . The resistance of the wire will be:

$5 \times 10^{- 5} Ω$

$3 \times 10^{- 6} Ω$

$46 \times 10^{6} Ω$

$2 \times 10^{6} Ω$

Q. The specific resistance of wire of length 1 m, area .of cross-section 0.5m2 is 25μΩm . The resistance of the wire will be:

5×10−5Ω

3×10−6Ω

46×106Ω

2×106Ω

Q. The specific resistance of wire of length 1 m, area .of cross-section $0.5 m^{2}$ is $25 μ Ω m$ . The resistance of the wire will be:

$5 \times 10^{- 5} Ω$

$3 \times 10^{- 6} Ω$

$46 \times 10^{6} Ω$

$2 \times 10^{6} Ω$