The specific heat at constant volume for the monoatomic argon is 0.075 kcal / kg - K, whereas its gram molecular specific heat is CV=2.98 cal / mol K. The mass of the carbon atom is

Question

The specific heat at constant volume for the monoatomic argon is 0.075 kcal / kg - K, whereas its gram molecular specific heat is CV=2.98 cal / mol K. The mass of the carbon atom is (A) 6.60 × 10-23 g (B) 3.30 × 10-23 g (C) 2.20 × 10-23 g (D) 13.20 × 10-23 g

Tardigrade Admin · Accepted Answer

Molar specific heat = Molecular weight x gram specific heat. CV =M × cV 2.98 cal / mol - K =M × 0.075 kcal / kg - K =(M × 0.075 × 103/103) cal / g - K ∴ Molecular weight of argon, M=(2.98/0.075)=39.7 g i.e. mass of 6.023 × 1023 atom =39.7 g Therefore, mass of single atom =(39.7/6.023 × 1023) =6.60 × 10-23 g

Q. The specific heat at constant volume for the monoatomic argon is $0.075 k c a l / k g - K$ , whereas its gram molecular specific heat is $C_{V} = 2.98 c a l / m o l K$ . The mass of the carbon atom is

$6.60 \times 1 0^{- 23} g$

$3.30 \times 1 0^{- 23} g$

$2.20 \times 1 0^{- 23} g$

$13.20 \times 1 0^{- 23} g$

Q. The specific heat at constant volume for the monoatomic argon is 0.075kcal/kg−K, whereas its gram molecular specific heat is CV​=2.98cal/molK. The mass of the carbon atom is

6.60×10−23g

3.30×10−23g

2.20×10−23g

13.20×10−23g

Molar specific heat = Molecular weight x gram specific heat. CV​=M×cV​ 2.98cal/mol−K=M×0.075kcal/kg−K =103M×0.075×103​cal/g−K ∴ Molecular weight of argon, M=0.0752.98​=39.7g i.e. mass of 6.023×1023 atom =39.7g Therefore, mass of single atom =6.023×102339.7​ =6.60×10−23g

Q. The specific heat at constant volume for the monoatomic argon is $0.075 k c a l / k g - K$ , whereas its gram molecular specific heat is $C_{V} = 2.98 c a l / m o l K$ . The mass of the carbon atom is

$6.60 \times 1 0^{- 23} g$

$3.30 \times 1 0^{- 23} g$

$2.20 \times 1 0^{- 23} g$

$13.20 \times 1 0^{- 23} g$