The specific conductance of a N / 10 KCl at 25° C is 0.0112 ohm -1 cm -1 . The resistance of cell containing solution at the same temperature was found to be 55 ohm. The cell constant will be

Question

The specific conductance of a N / 10 KCl at 25° C is 0.0112 ohm -1 cm -1 . The resistance of cell containing solution at the same temperature was found to be 55 ohm. The cell constant will be (A) 0.142 cm-1  (B) 0.66 cm-1  (C) 0.918 cm-1  (D) 1.12 cm-1

Tardigrade Admin · Accepted Answer

Specific conductivity, k=0.012 Ω-1 cm -1 k=(1/ text resistance ) × (1/a)[G=(1/R)] (1/a)= cell constant (1/a)=55 × 0.012=0.66 cm -1

Q. The specific conductance of a $N /10 K Cl$ at $2 5^{\circ} C$ is $0.0112 o h m^{- 1} c m^{- 1} .$ The resistance of cell containing solution at the same temperature was found to be $55 o hm$ . The cell constant will be

0.142 $c m^{- 1}$

0.66 $c m^{- 1}$

0.918 $c m^{- 1}$

1.12 $c m^{- 1}$

Specific conductivity, $k = 0.012 Ω^{- 1} c m^{- 1}$
$k = \frac{1}{resistance} \times \frac{1}{a} [G = \frac{1}{R}]$
$\frac{1}{a} =$ cell constant
$\frac{1}{a} = 55 \times 0.012 = 0.66 c m^{- 1}$

Q. The specific conductance of a N/10KCl at 25∘C is 0.0112ohm−1cm−1. The resistance of cell containing solution at the same temperature was found to be 55ohm. The cell constant will be

0.142 cm−1

0.66 cm−1

0.918 cm−1

1.12 cm−1