Question

The solution set of the inequality $3(2-x)\ge 2(1-x)$ is ...B $B\dots$. Here, $B$ refers to

• A. $(-\infty ,4)$
• B. $(-\infty ,4]$
• C. $(-\infty ,-4)$
• D. $(-\infty ,-4]$

Answer 1

Answer: (B)

We have, $3(2-x)\ge 2(1-x)=6-3x\ge 2-2x$
Transferring the term 2 to LHS and the term $-3x$ to $RHS$,
$6-2\ge -2x+3x$
$\Rightarrow 4\ge x\Rightarrow x\le 4$