Tardigrade
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Tardigrade
Question
Chemistry
The solubility product of a sparingly soluble salt AX2 is 3.2 × 10-11 . Its solubility (in mol/L) is
Q. The solubility product of a sparingly soluble salt
A
X
2
is
3.2
×
1
0
−
11
. Its solubility (in mol/L) is
5093
215
AIPMT
AIPMT 2004
Equilibrium
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A
5.6
×
1
0
−
6
8%
B
3.1
×
1
0
−
4
10%
C
2
×
1
0
−
4
75%
D
4
×
1
0
−
4
7%
Solution:
A
X
2
→
x
A
2
+
+
2
x
2
X
−
K
s
p
=
4
x
3
;
x
=
3
4
3.2
×
1
0
−
11
;
x
=
2
×
1
0
−
4
mole / litre