Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The solubility product of a sparingly soluble metal hydroxide M ( OH )2 at 298 K is 5 × 10-16 mol 3 d m-9. The pH value of its aqueous and saturated solution is
Q. The solubility product of a sparingly soluble metal hydroxide
M
(
O
H
)
2
at
298
K
is
5
×
1
0
−
16
m
o
l
3
d
m
−
9
. The
p
H
value of its aqueous and saturated solution is
2496
201
J & K CET
J & K CET 2009
Equilibrium
Report Error
A
5
B
9
C
11.5
D
8.5
Solution:
M
(
O
H
)
2
⇋
s
M
+
+
2
s
2
O
H
−
K
s
p
=
(
s
)
(
2
s
)
2
=
4
s
3
=
5
×
1
0
−
16
∴
s
=
3
4
5
×
1
0
−
6
=
5
×
1
0
−
6
Conc. of
O
H
−
=
2
×
5
×
1
0
−
6
=
1
0
−
5
m
o
l
d
m
−
3
pO
H
=
−
lo
g
[
O
H
−
]
=
−
lo
g
1
0
−
5
=
5
p
H
=
14
−
pO
H
=
14
−
5
=
9.