The solubility of CaF2 in pure water is 2.3 × 10- 6 mol dm-3 . Its solubility product will be :

Question

The solubility of CaF2 in pure water is 2.3 × 10- 6 mol dm-3 . Its solubility product will be : (A)  4.8 × 10-18  (B)  48.66 × 10-18  (C)  4.9× 10-11  (D)  48.66 × 10-15

Tardigrade Admin · Accepted Answer

CaF2 qquad underset textsCa2+ + underset text2s2F- KSP = s(2s)2 = 4s3 KSP = 4 (2.3 × 10-6)3 48.668 × 10-18 (mol dm-3)3

Q. The solubility of $C a F_{2}$ in pure water is $2.3 \times 1 0^{- 6} m o l d m^{- 3}$ . Its solubility product will be :

$4.8 \times 1 0^{- 18}$

$48.66 \times 1 0^{- 18}$

$4.9 \times 1 0^{- 11}$

$48.66 \times 1 0^{- 15}$

$C a F_{2}$ $s Ca X^{2 +}$ $+ 2s 2 F X^{-}$
$K_{SP} = s (2 s)^{2} = 4 s^{3}$
$K_{SP} = 4 (2.3 \times 1 0^{- 6})^{3}$
$48.668 \times 1 0^{- 18} (m o l d m^{- 3})^{3}$

Q. The solubility of CaF2​ in pure water is 2.3×10−6moldm−3 . Its solubility product will be :

4.8×10−18

48.66×10−18

4.9×10−11

48.66×10−15