Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
The solubility of Ca ( OH )2 in water is [Given: The solubility product of Ca ( OH )2 in water .=5.5 × 10-6]
Q. The solubility of
C
a
(
O
H
)
2
in water is [Given : The solubility product of
C
a
(
O
H
)
2
in water
=
5.5
×
1
0
−
6
]
3713
258
JEE Main
JEE Main 2021
Equilibrium
Report Error
A
1.77
×
1
0
−
6
0%
B
1.11
×
1
0
−
6
0%
C
1.11
×
1
0
−
2
67%
D
1.77
×
1
0
−
2
33%
Solution:
C
a
(
O
H
)
2
⇌
C
s
2
+
S
(
a
q
)
+
2
O
H
−
2
S
(
a
q
)
k
s
p
=
s
(
2
s
)
2
⇒
5.5
×
1
0
−
6
=
4
S
3
⇒
s
=
(
4
5.5
)
3
1
×
1
0
−
2
=
1.11
×
1
0
−
2