Question

The solubility of $AgI$ in $NaI$ solution is less than that in pure water because

• A. $AgI$ forms complex with $NaI$
• B. of common ion effect
• C. solubility product of $AgI$ is less
• D. the temperature of the solution decrease

Answer 1

Answer: (B)

The solubility of $AgI$ in $NaI$ solution is less than that in pure water because solubility is decreased due to common ion effect.
$AgI\rightleftharpoons A{g}^{+}+I^{-}$
$NaI\rightleftharpoons N{a}^{+}+\underset{commonion}{I^{-}}$