Question

The slope of the tangent to the hyperbola $2x^2-3y^2=6$ at $(3,2)$ is

• A. -1
• B. 1
• C. 0
• D. 2

Answer 1

Answer: (B)

Differentiating the given equation of the curve
$4x-6y.(dy/dx)=0$
$\therefore dy/dx=2x/3y$
${\left(\frac{dy}{dx}\right)}_{(3,2)}=\frac{2}{3}\cdot \frac{3}{2}=1$