The slope of the kinetic energy versus position vector gives the rate of change of

Question

The slope of the kinetic energy versus position vector gives the rate of change of (A) momentum (B) velocity (C) force (D) power

Tardigrade Admin · Accepted Answer

We know that, kinetic energy (KE) =(1/2)mv2 Also ,force × displacement =(1/2)mv2 ⇒ F=(1/2)m(v2/d)=(KE/d) Hence, slope of kinetic energy versus position vector gives the rate of change of force.

Q. The slope of the kinetic energy versus position vector gives the rate of change of

momentum

velocity

force

power

We know that, kinetic energy (KE) = $\frac{1}{2} m v^{2}$
Also ,force $\times$ displacement $= \frac{1}{2} m v^{2}$
$\Rightarrow F = \frac{1}{2} m \frac{v ^{2}}{d} = \frac{K E}{d}$
Hence, slope of kinetic energy versus position vector gives the rate of change of force.

Q. The slope of the kinetic energy versus position vector gives the rate of change of

momentum

velocity

force

power

We know that, kinetic energy (KE) =21​mv2 Also ,force × displacement =21​mv2 ⇒F=21​mdv2​=dKE​ Hence, slope of kinetic energy versus position vector gives the rate of change of force.

We know that, kinetic energy (KE) = $\frac{1}{2} m v^{2}$
Also ,force $\times$ displacement $= \frac{1}{2} m v^{2}$
$\Rightarrow F = \frac{1}{2} m \frac{v ^{2}}{d} = \frac{K E}{d}$
Hence, slope of kinetic energy versus position vector gives the rate of change of force.