The set of quantum numbers not applicable for an electron in an atoms is

Question

The set of quantum numbers not applicable for an electron in an atoms is (A) n=1, l=1, ml=1, ms=+(1/2) (B) n=1, l=0, ml=0, ms=+(1/2) (C) n=2 ,l=1, ml=1, ms=-(1/2) (D) n=2, l=0, ml=0, ms=+(1/2)

Tardigrade Admin · Accepted Answer

If n=1 then l=0, because l= zero to (n-1) any integral value. So, value of l never be equal to n. m=-l to +l including zero So, if l=0, m never be equal to 1 Hence, the given set of quantum number is not applicable. n=1, l=1, ml=1, ms=+(1/2)

Q. The set of quantum numbers not applicable for an electron in an atoms is

$n = 1, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$

$n = 1, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}$

$n = 2, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}$

$n = 2, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}$

If $n = 1$
then $l = 0$ , because $l =$ zero to $(n - 1)$ any integral value.
So, value of $l$ never be equal to $n$ .
$m = - l$ to $+ l$ including zero
So, if $l = 0, m$ never be equal to $1$
Hence, the given set of quantum number is not applicable.
$n = 1, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$

Q. The set of quantum numbers not applicable for an electron in an atoms is

n=1,l=1,ml​=1,ms​=+21​

n=1,l=0,ml​=0,ms​=+21​

n=2,l=1,ml​=1,ms​=−21​

n=2,l=0,ml​=0,ms​=+21​

If n=1 then l=0, because l= zero to (n−1) any integral value. So, value of l never be equal to n. m=−l to +l including zero So, if l=0,m never be equal to 1 Hence, the given set of quantum number is not applicable. n=1,l=1,ml​=1,ms​=+21​

$n = 1, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$

$n = 1, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}$

$n = 2, l = 1, m_{l} = 1, m_{s} = - \frac{1}{2}$

$n = 2, l = 0, m_{l} = 0, m_{s} = + \frac{1}{2}$

If $n = 1$
then $l = 0$ , because $l =$ zero to $(n - 1)$ any integral value.
So, value of $l$ never be equal to $n$ .
$m = - l$ to $+ l$ including zero
So, if $l = 0, m$ never be equal to $1$
Hence, the given set of quantum number is not applicable.
$n = 1, l = 1, m_{l} = 1, m_{s} = + \frac{1}{2}$