The self inductance of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be

Question

The self inductance of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be (A)  40 × 10-4 Wb (B) 0.04 Wb (C) 4 μ Wb (D) 40 m Wb

Tardigrade Admin · Accepted Answer

Given, n=500 L =50 mH =50 × 10-3 H and i =8 mA =8 × 10-3 A The magnetic flux linked with the coil is φ =L i=50 × 10-3 × 8 × 10-3 =400 × 10-6=4 × 10-4 Wb .

Q. The self inductance of a coil having 500 turns is $50 m H$ . The magnetic flux through the cross-sectional area of the coil while current through it is $8 m A$ is found to be

$40 \times 1 0^{- 4}$ Wb

$0.04$ Wb

$4 μ Wb$

$40 mWb$

Given, $n = 500$
$L = 50 m H = 50 \times 1 0^{- 3} H$
and $i = 8 m A = 8 \times 1 0^{- 3} A$
The magnetic flux linked with the coil is
$ϕ = L i = 50 \times 1 0^{- 3} \times 8 \times 1 0^{- 3}$
$= 400 \times 1 0^{- 6} = 4 \times 1 0^{- 4} Wb .$

Q. The self inductance of a coil having 500 turns is 50mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8mA is found to be

40×10−4 Wb

0.04 Wb

4μWb

40mWb