The sap in tree rises in a system of capillaries of radius 2.5 × 10-5 m. The surface tension of sap is 7.28 × 10-2 N m-1 and the angle of contact is 0°. The maximum height to which sap can rise in a tree through capillarity action is (ρsap=103 kg m-3)

Question

The sap in tree rises in a system of capillaries of radius 2.5 × 10-5 m. The surface tension of sap is 7.28 × 10-2 N m-1 and the angle of contact is 0°. The maximum height to which sap can rise in a tree through capillarity action is (ρsap=103 kg m-3) (A) 0.21 m (B) 0.59 m (C) 0.87 m (D) 0.91 m

Tardigrade Admin · Accepted Answer

Here, r=2.5×10-5 m, S=7.28×10-2 N m-1 Angle of contact, θ=0°, ρ=103 kg m-3 The maximum height to which the sap can rise bycapillary action is, h=(2S cos θ/r ρ g)=(2×7.28×10-2× cos 0°/2.5×10-5×103×9.8) = 0.59 m

$0.21 m$

$0.59 m$

$0.87 m$

$0.91 m$

Q. The sap in tree rises in a system of capillaries of radius 2.5×10−5m. The surface tension of sap is 7.28×10−2Nm−1 and the angle of contact is 0∘. The maximum height to which sap can rise in a tree through capillarity action is (ρsap​=103kgm−3)

0.21m

0.59m

0.87m

0.91m

Here, r=2.5×10−5m,S=7.28×10−2Nm−1 Angle of contact, θ=0∘,ρ=103kgm−3 The maximum height to which the sap can rise bycapillary action is, h=rρg2Scosθ​=2.5×10−5×103×9.82×7.28×10−2×cos0∘​ =0.59m

$0.21 m$

$0.59 m$

$0.87 m$

$0.91 m$