Question

The rubber cord of a catapult has a cross sectional area $1m{m}^2$ & total unstretchcdlength 10cm. It is stretched to 12cm & then released to project a missile of mass 5gm. Taking 'Y' for rubber $5\times 10^{8}N/m^2$, the velocity of projection is

• A. 10m/s
• B. 15 m/s
• C. 20m/s
• D. 25 m/s

Answer 1

Answer: (C)

$\nu =e\sqrt{\frac{YA}{ml}}$