The rms speed of N2 molecules in a gas is u. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms, the rms speed becomes

Question

The rms speed of N2 molecules in a gas is u. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms, the rms speed becomes (A) u/2 (B) 2u (C) 4u (D) 14u

Tardigrade Admin · Accepted Answer

(u1/u2)=√(n1T1/n2T2) =√(n× T/2n×2T) =√(1/4)=(1/2) u2=2u1=2u

Q. The $r m s$ speed of $N_{2}$ molecules in a gas is $u$ . If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms, the $r m s$ speed becomes

$u /2$

$2 u$

$4 u$

$14 u$

$\frac{u _{1}}{u _{2}} = \frac{n _{1} T _{1}}{n _{2} T _{2}}$
$= \frac{n \times T}{2 n \times 2 T}$
$= \frac{1}{4} = \frac{1}{2}$
$u_{2} = 2 u_{1} = 2 u$

Q. The rms speed of N2​ molecules in a gas is u. If the temperature is doubled and the nitrogen molecules dissociate into nitrogen atoms, the rms speed becomes

u/2

2u

4u

14u