The resultant of two vectors is perpendicular to first vector of magnitude 6 N . If the resultant has magnitude 6√3 text N , then magnitude of second vector is

Question

The resultant of two vectors is perpendicular to first vector of magnitude 6 N . If the resultant has magnitude 6√3 text N , then magnitude of second vector is (A) 6√2 N (B) 12 N (C) 9√3 N (D) 6√3 N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-nhl3nkc9evla.png" /> B Cos θ =6 B Sin θ =6√3 textB=√62 + (6 √3)2=12

Q. The resultant of two vectors is perpendicular to first vector of magnitude $6 N$ . If the resultant has magnitude $63 N$ , then magnitude of second vector is

$62 N$

$12 N$

$93 N$

$63 N$

$BC os θ = 6$
$BS in θ = 63$
$B = 6^{2} + (63)^{2} = 12$

Q. The resultant of two vectors is perpendicular to first vector of magnitude 6N . If the resultant has magnitude 63​ N , then magnitude of second vector is

62​N

12N

93​N

63​N