Tardigrade
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Tardigrade
Question
Physics
The rest energy of an electron is 0.511 MeV The electron is accelerated from rest to a velocity 0.5 c. The change in its energy will be
Q. The rest energy of an electron is
0.511
M
e
V
The electron is accelerated from rest to a velocity
0.5
c
. The change in its energy will be
2096
200
Chhattisgarh PMT
Chhattisgarh PMT 2005
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A
0.026 MeV
B
0.051 MeV
C
0.079 MeV
D
0.105 MeV
Solution:
The relation between the rest energy and moving energy is
E
=
1
−
v
2
/
c
2
E
0
∵
v
=
0.5
c
∴
E
=
1
−
0.25
E
0
=
0.75
E
0
Change in energy
Δ
E
=
E
−
E
0
=
0.75
E
0
−
E
0
=
E
0
(
0.75
1
−
1
)
=
0.511
(
0.75
1
−
1
)
=
0.079
M
e
V