The relative velocity of two parallel layers of water is 8 cm / sec. If the perpendicular distance between the layers is 0.1 cm. Then velocity gradient will be

Question

The relative velocity of two parallel layers of water is 8 cm / sec. If the perpendicular distance between the layers is 0.1 cm. Then velocity gradient will be (A) 80 / sec (B) 60 / sec (C) 50 / sec (D) 40 / sec

Tardigrade Admin · Accepted Answer

d v=8 cm / s and dx =0.1 cm Velocity gradient =( dv / dx )=(8/0.1)=80 / s

Q. The relative velocity of two parallel layers of water is $8 c m / sec$ . If the perpendicular distance between the layers is $0.1 c m$ . Then velocity gradient will be

$80/ sec$

$60/ sec$

$50/ sec$

$40/ sec$

$d v = 8 c m / s$ and $d x = 0.1 c m$
Velocity gradient $= \frac{d v}{d x} = \frac{8}{0.1} = 80/ s$

Q. The relative velocity of two parallel layers of water is 8cm/sec. If the perpendicular distance between the layers is 0.1cm. Then velocity gradient will be

80/sec

60/sec

50/sec

40/sec