Question

The relationship between the force $F$ and position $x$ of a body is as shown in the figure. The work done in displacing the body from $x=1m$ to $x=5m$ will be

• A. 30 J
• B. 15 J
• C. 25 J
• D. 20 J

Answer 1

Answer: (B)

Step1: Calculation of work done
As work done = area enclosed by F-x graph
Work done in displacing the body from $x=1m$ to $x=5m$ will be: $W=$ Area of ABNM + Area of CDEN-Area of EFGH + Area of HIJ (Area of EF GH is taken negative as the force is in negative direction) \Rightarrow W =(1 \times 10)+(1 \times 5)-(1 \times 5)+\left(\frac{1}{2} \times 10 \times 1\right)=15 J So, the work done in displacing the body from $x=1m$ to $x=5m$ will be $15J$.