The relationship between kinetic energy (K) and potential energy (U) of electron moving in a orbit around the nucleus is

Question

The relationship between kinetic energy (K) and potential energy (U) of electron moving in a orbit around the nucleus is (A) U = -K (B) U = -2K (C) U = - 3K (D) U = -(1/2)K

Tardigrade Admin · Accepted Answer

Kinetic energy, K =(1/2)mv2 = (e2/8πε0 r) and P.E., U = - (e2/4πε0r) or K =(1/2)mv2 = (e2/8π ε0r) ⇒ U = -2 K .

Q. The relationship between kinetic energy $(K)$ and potential energy $(U)$ of electron moving in a orbit around the nucleus is

$U = - K$

$U = - 2 K$

$U = - 3 K$

$U = - \frac{1}{2} K$

Kinetic energy,
$K = \frac{1}{2} m v^{2} = \frac{e ^{2}}{8 π ε _{0} r}$ and
$P . E ., U = - \frac{e ^{2}}{4 π ε _{0} r}$
or $K = \frac{1}{2} m v^{2} = \frac{e ^{2}}{8 π ε _{0} r}$
$\Rightarrow U = - 2 K$ .

Q. The relationship between kinetic energy (K) and potential energy (U) of electron moving in a orbit around the nucleus is

U=−K

U=−2K

U=−3K

U=−21​K